LeetCode Database 262 行程和用户

1. 题目描述

Trips 表中存所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。

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+----+-----------+-----------+---------+--------------------+----------+
| Id | Client_Id | Driver_Id | City_Id | Status |Request_at|
+----+-----------+-----------+---------+--------------------+----------+
| 1 | 1 | 10 | 1 | completed |2013-10-01|
| 2 | 2 | 11 | 1 | cancelled_by_driver|2013-10-01|
| 3 | 3 | 12 | 6 | completed |2013-10-01|
| 4 | 4 | 13 | 6 | cancelled_by_client|2013-10-01|
| 5 | 1 | 10 | 1 | completed |2013-10-02|
| 6 | 2 | 11 | 6 | completed |2013-10-02|
| 7 | 3 | 12 | 6 | completed |2013-10-02|
| 8 | 2 | 12 | 12 | completed |2013-10-03|
| 9 | 3 | 10 | 12 | completed |2013-10-03|
| 10 | 4 | 13 | 12 | cancelled_by_driver|2013-10-03|
+----+-----------+-----------+---------+--------------------+----------+

Users 表存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。

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+----------+--------+--------+
| Users_Id | Banned | Role |
+----------+--------+--------+
| 1 | No | client |
| 2 | Yes | client |
| 3 | No | client |
| 4 | No | client |
| 10 | No | driver |
| 11 | No | driver |
| 12 | No | driver |
| 13 | No | driver |
+----------+--------+--------+

写一段 SQL 语句查出 2013年10月1日2013年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。

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+------------+-------------------+
| Day | Cancellation Rate |
+------------+-------------------+
| 2013-10-01 | 0.33 |
| 2013-10-02 | 0.00 |
| 2013-10-03 | 0.50 |
+------------+-------------------+

2. 题解

2.1. MySQL

取消率由Status字段决定。Status字段的值可以为completed、cancelled_by_driver、cancelled_by_client,只有completed代表不取消,其它两个值就代表取消。那么取消率就是cancelled_by_driver和cancelled_by_client所占的比例

这里可以用CASE语句来统计,只有completed状态视为0,其它状态视为1,累加起来,最除以总数COUNT(*),就是取消率

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CASE 
WHEN tb1.Status = 'completed' THEN 0
ELSE 1
END

ROUND(value, n) 表示对value四舍五入保留N位小数

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-- 正确做法
SELECT tb1.Request_at AS Day, (
ROUND(SUM(CASE WHEN tb1.Status = 'completed' THEN 0
ELSE 1
END) / COUNT(*), 2)) AS 'Cancellation Rate'
FROM Trips tb1
JOIN Users tb2
ON tb1.Client_Id = tb2.Users_Id AND tb2.Banned = 'No' -- Client是非禁止用户
JOIN Users tb3
ON tb1.Driver_id = tb3.Users_Id AND tb3.Banned = 'No' -- Driver是非禁止用户
WHERE tb1.Request_at BETWEEN '2013-10-01' AND '2013-10-03' -- 2013年10月1日 至 2013年10月3日
GROUP BY tb1.Request_at -- 分组统计
ORDER BY Day -- 日期从小到大
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